math questions?

1) in an archery contest, each person invovled fire Mush first time in a vertical position of the target 40 m and the second time in 60 feet of the goal. the probability of success was married to a distance of 40 m is that three quarters of their likelihood to succeed in a distance of 60m. What is the probability of success in the two shots? * The answer is 3 / 40, but I need help on how to get there, I do not understand how. 2) casino night stands two dice rolled whoes EDC faces were counted 6.1 What is the probability that the sum of the numbers on the top of the die is greater than or equal to 6, but for fear of 10?

The first question seems to be missing probablility success of 60m. But the calculation of the two probabliity all Itiro is simply multiply both. From anwswer is returned to the monitoring and understanding of the probability of i. m 60. 75 * X = 3-40, where X =. 10. I do not know if it could be the summer is the distance of 40m and 60m, or if you forgot to give him the chance. For the second single, but his time. There are a total of 21 combinations given. (1 & 1, 1, 2, 1 and 3 and so on ….. up to 6 and 6). and need to count the total number of combinations that correspond with the limits equal or greater than 6 but less than 10. I had a total of 11. Then simply divide the two: 11 / 21 =. 5238 or 52.4%

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